Binary Tree Maximum Path Sum

Last updated: March 3, 2025

Quick Overview

Find the maximum path sum in a binary tree where the path can start and end at any node. Tests recursive tree traversal with global state.

ByteDance
Coding & Algorithms
Software Engineer
ByteDance
March 3, 2025
Software Engineer
Coding Round
Coding & Algorithms
Hard

5

8

4,064 solved


Find the maximum path sum in a binary tree where the path can start and end at any node. Tests recursive tree traversal with global state.

Tree problems are a top-5 pattern at ByteDance. This hard variant requires careful handling of negative values and path constraints.

What the Interviewer Expects
  • Implement recursive DFS with post-order traversal
  • Track global maximum across all recursive calls
  • Handle negative node values correctly
  • Understand the difference between path through a node and path ending at a node
  • Discuss time and space complexity
Key Topics to Cover
Binary tree
DFS
Post-order traversal
Path problems
Global state in recursion
How to Approach This
  1. Clarify input constraints and edge cases before writing code.
  2. Walk through your approach verbally and confirm with the interviewer before coding.
  3. Start with a brute force solution, then optimize. Mention time and space complexity.
  4. Test your solution with examples, including edge cases like empty input or duplicates.
  5. Consider common patterns: sliding window, two pointers, hash map, BFS/DFS, dynamic programming.
Possible Follow-up Questions
  • How would you return the actual path, not just the sum?
  • What if the tree has billions of nodes?
  • How would you handle this on a tree stored on disk?
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Sample Answer
Problem Analysis

The problem requires us to find the maximum path sum in a binary tree, where the path can start and end at any node. This prompts the use of a depth-first search (DFS) approach, specifically post-orde...

Approach
  1. Define a Recursive Function: Create a helper function that takes the current node as input and computes the maximum path sum from that node.
  2. Base Case: If the current node is None, re...

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