Detect subsequence in array
Last updated: August 27, 2025
Quick Overview
Given array, detect all occurrences of the anagram pattern.
Palantir
August 27, 202594
13
4,741 solved
Given array, detect all occurrences of the anagram pattern.
This coding problem is frequently asked during Technical Screen at Palantir. The interviewer is testing your ability to translate a problem into clean, working code while discussing time and space complexity. Palantir expects candidates to write production-quality code, not just solve the puzzle.
What the Interviewer Expects
- Recognize the underlying problem pattern (sliding window, two pointers, BFS/DFS, etc.)
- Discuss multiple approaches and trade-offs before coding
- Implement an optimal solution with clean, production-quality code
- Handle all edge cases including boundary conditions and invalid input
- Optimize both time and space complexity with clear justification
- Test your solution systematically with well-chosen examples
Key Topics to Cover
How to Approach This
- Clarify input constraints and edge cases before writing code.
- Walk through your approach verbally and confirm with the interviewer before coding.
- Start with a brute force solution, then optimize. Mention time and space complexity.
- Test your solution with examples, including edge cases like empty input or duplicates.
- Consider common patterns: sliding window, two pointers, hash map, BFS/DFS, dynamic programming.
Possible Follow-up Questions
- Can you solve this iteratively instead of recursively (or vice versa)?
- How would your solution change if the input was sorted?
- What if the input doesn't fit in memory?
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Problem Analysis
To detect all occurrences of an anagram pattern within an array, we can utilize the sliding window technique. This is applicable here because we need to efficiently check if any contiguous subsequ...
Approach
- Character Frequency Count: First, we need to create a frequency count of the characters in the anagram pattern. For example, if the pattern is 'abc', the frequency count will be {'a': 1, 'b': 1...
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