Find the Lowest Common Ancestor in a Binary Tree

Last updated: August 1, 2026

Quick Overview

The candidate is asked to find the lowest common ancestor (LCA) of two nodes in a binary tree.

Amazon
Coding & Algorithms
Software Engineer
Amazon
August 1, 2026
Software Engineer
Technical Screen
Coding & Algorithms
Easy

4

0

31 solved


The candidate is asked to find the lowest common ancestor (LCA) of two nodes in a binary tree.

This question is commonly asked during technical screens to assess a candidate's understanding of tree data structures and their ability to solve problems using algorithms. The interviewer is evaluating the candidate's problem-solving skills, coding proficiency, and understanding of binary trees, which are fundamental concepts in software engineering.

What the Interviewer Expects
  • Explain the concept of the lowest common ancestor clearly.
  • Describe the approach to traverse the binary tree.
  • Provide a working algorithm with a clear explanation of its logic.
  • Discuss the time and space complexity of the solution.
  • Write clean and efficient code.
Key Topics to Cover
Binary Trees
Lowest Common Ancestor
Tree Traversal
Recursion
Time Complexity
How to Approach This
  1. Clarify input constraints and edge cases before writing code.
  2. Walk through your approach verbally and confirm with the interviewer before coding.
  3. Start with a brute force solution, then optimize. Mention time and space complexity.
  4. Test your solution with examples, including edge cases like empty input or duplicates.
  5. Consider common patterns: sliding window, two pointers, hash map, BFS/DFS, dynamic programming.
Possible Follow-up Questions
  • How would you modify your solution for a binary search tree?
  • What if the tree is not a binary tree?
  • Can you optimize your solution for space complexity?
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Sample Answer
Approach

To find the lowest common ancestor of two nodes in a binary tree, we can use a recursive approach. The idea is to traverse the tree starting from the root and check if the current node is one of the n...

Algorithm

Here's a Python implementation of the algorithm:

class TreeNode: def __init__(self, val=0, left=None, right=None): self.val = val self.left = left self.right = r...

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