rotation on Binary Tree
Last updated: April 12, 2026
Quick Overview
Perform a rotation on a binary tree and return the result.
Grubhub
April 12, 20266
4
2,887 solved
Perform a rotation on a binary tree and return the result.
This coding problem is frequently asked during Onsite at Grubhub. The interviewer is testing your ability to translate a problem into clean, working code while discussing time and space complexity. Grubhub expects candidates to write production-quality code, not just solve the puzzle.
What the Interviewer Expects
- Identify the correct data structure and algorithm for the problem
- Write clean, bug-free code with proper variable naming
- Analyze time and space complexity correctly
- Handle basic edge cases (empty input, single element)
- Communicate your thought process while coding
Key Topics to Cover
How to Approach This
- Clarify input constraints and edge cases before writing code.
- Walk through your approach verbally and confirm with the interviewer before coding.
- Start with a brute force solution, then optimize. Mention time and space complexity.
- Test your solution with examples, including edge cases like empty input or duplicates.
- Consider common patterns: sliding window, two pointers, hash map, BFS/DFS, dynamic programming.
Possible Follow-up Questions
- What is the worst-case input for your solution?
- How would your solution change if the input was sorted?
- Can you optimize the space complexity of your solution?
- How would you modify your solution to handle streaming input?
Sharpen Your Skills on Codemia
Practice similar problems with our interactive workspace, get AI feedback, and track your progress.
Practice DSA ProblemsSample Answer
Problem Analysis
To perform a rotation on a binary tree, we need to identify the type of rotation. A common rotation is a right or left rotation, which can be viewed as a restructuring of the tree to maintain the bina...
Approach
- Identify Rotation Node: Assume we are given a node
xwhere the rotation will be performed. - Perform Right Rotation:
- Set
newRoottox.left. - Set
x.leftto `newRoot.righ...
- Set