multithreading
condition_variable
concurrency
lock
C++ programming

Do I have to acquire lock before calling condition_variable.notify_one?

Interview Questions practice on Codemia

Over 8,000 real interview questions from top companies, searchable by company and role.

Browse interview questions

In multithreaded programming within the realm of C++, dealing with synchronization primitives like std::mutex and std::condition_variable is crucial to ensure data integrity and coordinate thread execution. One common question that developers encounter is whether it is necessary to acquire a lock before calling condition_variable::notify_one(). Let’s delve into this topic to provide a comprehensive understanding.

Understanding std::condition_variable

In C++, std::condition_variable is typically used alongside a mutex to block a thread until a particular condition is met. This is done to efficiently synchronize different threads without the need for busy waiting. Here is how a typical scenario looks when a thread needs to wait for a condition:

cpp
1std::mutex m;
2std::condition_variable cv;
3bool ready = false;
4
5void wait_for_condition() {
6    std::unique_lock<std::mutex> lock(m);  // Acquire the lock
7    cv.wait(lock, [] { return ready; });   // Wait for condition to be met
8    // Proceed once the condition is true
9}

The Role of notify_one()

The notify_one() function is used to unblock at least one of the threads that are waiting on the condition_variable. An important aspect to note is the relationship between notify_one() and the mutex.

Do You Need to Acquire a Lock?

Technically, you do not need to hold the lock when calling condition_variable::notify_one(). The C++ standard even makes it clear by stating that notify_one() and notify_all() do not require a lock to be held. Here's how one might use notify_one():

cpp
1void signal_condition() {
2    std::lock_guard<std::mutex> lock(m);  // Acquire the lock
3    ready = true;                         // Change the shared data
4    // No need to hold the lock for notify_one
5    cv.notify_one();
6}

However, the above implementation demonstrates acquiring a lock while modifying ready. This is crucial to ensure data integrity as multiple threads may be accessing or modifying ready.

Why Acquire a Lock Before notify_one()?

While it's not a requirement, holding the lock around notify_one() can be beneficial:

  1. Data Consistency: If you change the condition variable's associated shared data before calling notify_one(), it’s often done under the protection of a mutex to serialize access and ensure data consistency.
  2. Avoiding Missed Notifications: There’s a subtle race condition that could potentially arise:
    • Thread A sets the condition without acquiring the lock and calls notify_one().
    • Thread B is not yet waiting on the condition_variable when the notification occurs.
    • Thread B subsequently calls wait() and may block indefinitely. Using a lock ensures that the condition check within the wait loop is serialized with updates to the data.

A Practical Example

Let’s look at an application that uses condition_variable where acquiring a lock is clearly beneficial:

cpp
1#include <iostream>
2#include <mutex>
3#include <condition_variable>
4#include <thread>
5
6std::mutex m;
7std::condition_variable cv;
8bool ready = false;
9
10void perform_task() {
11    std::unique_lock<std::mutex> lock(m);
12    cv.wait(lock, [] { return ready; });
13    std::cout << "Task performed!" << std::endl;
14}
15
16void make_ready() {
17    {
18        std::lock_guard<std::mutex> lock(m);
19        ready = true;
20    } // Lock is released here.
21    cv.notify_one(); // Notify waiting thread.
22}
23
24int main() {
25    std::thread worker(perform_task);
26    std::thread notifier(make_ready);
27
28    worker.join();
29    notifier.join();
30
31    return 0;
32}

Table: Key Points of notify_one()

AspectDetail
Lock HoldingNot mandatory to acquire a lock for notify_one() call.
Data ConsistencyChanges to condition data should involve a lock.
Avoid Missed NotificationsEmploy a lock to avoid race conditions.
Performancenotify_one() is generally lightweight and non-blocking.

Considerations and Best Practices

  • Use of notify_all(): If multiple threads are waiting, consider whether notify_all() is more appropriate.
  • Spurious Wake-ups: Remember that wait() can return unexpectedly and check the condition in a loop.
  • Design: Evaluate whether your threading model efficiently uses condition variables and mutexes together.

In summary, while it is not a technical requirement to use std::mutex before calling condition_variable::notify_one(), it is often a good practice to pair it with a lock to manage data consistency and prevent missed notifications. Properly leveraging these synchronization mechanisms is key to building robust multithreaded applications in C++.


Related reading
Free course
Beginner
7 lessons
2 hours
Tackling System Design Interview Problems

A short course that equips you with the skills to approach system design interviews methodically.

Start the free course
Track what you have practised

A free account saves your progress, solutions and study plan across every problem on Codemia.

Interview Questions practice on Codemia

Over 8,000 real interview questions from top companies, searchable by company and role.

Browse interview questions

All Rights Reserved.