Does stdcopy handle overlapping ranges?
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Introduction
std::copy does not safely handle overlapping ranges when the destination overlaps with the source in the forward direction. Using std::copy with overlapping ranges where the destination is within or ahead of the source produces undefined behavior. For overlapping ranges, use std::copy_backward (when the destination is after the source) or std::move/std::memmove for raw memory.
std::copy Signature
- Parameters:
first,last: Iterators to the initial and final position in the source ranged_first: Iterator to the beginning of the destination range
- Return Value: An iterator to the element past the last element copied
When Overlapping Is Dangerous
The problem: std::copy copies left to right. When d_first is inside [first, last), earlier copies overwrite values that later copies need to read.
Safe Overlapping with std::copy_backward
std::copy_backward copies from right to left, which is safe when the destination is after the source:
When to Use Which
| Scenario | Safe Function |
| No overlap | std::copy or std::copy_backward |
| Destination before source | std::copy |
| Destination after source (overlap) | std::copy_backward |
| Destination inside source (forward) | std::copy_backward |
std::memmove for Raw Memory
For raw memory (C-style arrays, trivially copyable types), std::memmove handles all overlapping cases:
std::memmove vs std::memcpy:
std::memcpy: undefined for overlapping ranges (likestd::copy)std::memmove: safe for overlapping ranges (uses temporary buffer or reverse copy internally)
std::move for Move Semantics
std::move (the algorithm, not std::move for rvalue references) moves elements instead of copying:
Practical Examples
Shifting Elements Right
Shifting Elements Left
Insert Into a Sorted Array
Common Pitfalls
- Assuming std::copy is safe: Unlike
memmove,std::copydoes not handle overlapping ranges. Always check if source and destination overlap before choosing the algorithm. - Wrong direction:
std::copy_backwardrequiresd_last(end of destination), notd_first. It copies from[first, last)to[d_last - (last - first), d_last). - Non-trivial types:
std::memmoveonly works for trivially copyable types (PODs, primitive types). For objects with constructors/destructors, usestd::copy_backward. - Off-by-one:
std::copy_backward(first, last, d_last)copieslast - firstelements ending atd_last. Ensured_lastpoints one past the end of the destination. - Range validation: Neither
std::copynorstd::copy_backwardchecks that the destination has enough space. Writing past the end of a container is undefined behavior.
Summary
std::copydoes not handle overlapping ranges — undefined behavior if destination is inside the source range- Use
std::copy_backwardwhen the destination is after (and overlaps with) the source - Use
std::memmovefor safe overlapping copies of trivially copyable types std::memcpyandstd::copyhave the same restriction: no overlap allowed- Always analyze the overlap direction to choose the correct algorithm
Related reading
- Does stdcopy_n work with overlapping ranges?
- Does stdsort implement Quicksort?
- Does the dataset size influence a machine learning algorithm?
- Does the range-based 'for' loop deprecate many simple algorithms?
- Does the C volatile keyword introduce a memory fence?
- Duplicate a LinkedList with a pointer to a random node apart from the next node
- Does there exist a Top Down Dynamic Programming solution for Longest Increasing Subsequence?
- Does this cause a real problem when I adopt the Raft's never commits log entries from previous terms by counting replicas rule in this situation?

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Data Structures & Algorithms practice on Codemia
Step through 300 algorithm problems with animated visualisers that show the data structure changing as the code runs.