How can I use escape characters with string interpolation in C 6?
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Introduction
C# 6 string interpolation combines two rules in one place: normal string escaping and expression placeholders written with braces. Most confusion comes from mixing quotes, backslashes, and literal braces inside the same interpolated string.
The good news is that C# 6 is consistent. Once you know when to use a regular interpolated string and when to use a verbatim interpolated string, escaping becomes predictable.
Regular Interpolated Strings
A standard interpolated string starts with $" and ends with ". Inside it, ordinary C# escape sequences still apply:
- '
\"for a literal double quote' - '
\\for a literal backslash' - '
\nfor a newline' - '
{expr}for interpolation'
Example:
The interpolation syntax does not replace normal string rules. It adds expression placeholders on top of them.
Literal Braces in an Interpolated String
Braces are special because they mark interpolation holes. If you want an actual brace character in the output, double it.
That prints text containing real braces around the content. If you write a single { or }, the compiler assumes you are starting or ending an interpolation expression.
This is the single most common source of errors when developers build JSON-like or template-like text with C# interpolation.
Verbatim Interpolated Strings
Paths and regex-heavy strings are often easier to read with a verbatim interpolated string:
In $@"..." strings:
- backslashes are literal
- quotes are escaped by doubling them as
"" - interpolation still uses braces
Example with embedded quotes:
This style is much easier to read than a regular interpolated string full of doubled backslashes.
C# 6 Versus Newer C# Versions
You may see examples online that use raw interpolated strings with triple quotes. Those are useful, but they are not part of C# 6. If the question is specifically about C# 6, your practical tools are:
- regular interpolated strings such as
$"..." - verbatim interpolated strings such as
$@"..." - doubled braces for literal brace output
That is enough to solve almost every escaping problem you will hit in C# 6 code.
A Complete Example
This sample shows the three most common cases together:
If you understand why each line uses its particular escaping style, you already have the mental model needed for C# 6 interpolation.
Common Pitfalls
The biggest mistake is forgetting that literal braces must be doubled.
Another common issue is over-escaping backslashes inside a verbatim interpolated string. In $@"C:\temp\file.txt", those backslashes are already literal.
A third problem is mixing quote rules. Regular interpolated strings use \", while verbatim interpolated strings use doubled quotes such as "".
Finally, be careful when copying examples from newer C# versions. Raw strings are helpful, but they do not answer a C# 6 question.
Summary
- C# 6 interpolation still follows normal string-literal escaping rules.
- Use
{{and}}to output literal braces. - Use
$@"..."for paths and other backslash-heavy text. - Standard interpolated strings escape quotes with
\"; verbatim ones use"". - Focus on C# 6 syntax, not newer raw-string features, when solving C# 6 interpolation problems.

