Why aren't stdalgorithms constexpr and which could be?
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Introduction
In the landscape of C++ programming, constexpr
plays a significant role in enabling compile-time computation, ultimately enhancing performance and ensuring safer code. While many functions and features in modern C++ benefit from constexpr
, the standard library's algorithms have been somewhat lagging in this regard. In this article, we'll delve into the reasons why some std::algorithms
are not constexpr
and explore which algorithms could potentially become constexpr
in the future.
Understanding constexpr
What is constexpr
?
The constexpr
specifier, introduced in C++11 and progressively enhanced in later standards, enables expressions to be evaluated at compile time. It ensures that a function or a constructor can be evaluated during the compilation, providing several advantages such as reduced runtime overhead and increased performance.
Benefits of constexpr
- Compile-Time Computation: Allows calculations to be done at compile time, reducing runtime cost.
- Type Safety: Ensures that operations are correctly formed and safe to perform before runtime.
- Performance Gains: Optimizes code by eliminating runtime computations and potentially reducing binary size.
Challenges with Making std::algorithms
constexpr
1. Dependency on Non-constexpr
Contexts
Many std::algorithms
operate on iterators, and these iterators often point to runtime data structures, such as standard containers (std::vector
, std::list
), which are inherently non-constexpr
. This poses a significant constraint:
- Example: Traversing a container like
std::vectorinvolves pointer arithmetic, which isn't allowed at compile-time unless all elements and the underlying storage model areconstexpr.
2. Side Effects and Undefined Behavior
std::algorithms
may involve operations with side effects or undefined behavior, both incompatible with constexpr
functions. For example:
- Mutation Operations: Algorithms like
std::transformorstd::for_eachmodify elements in-place, and the result must be observable without side effects, which is challenging to ensure at compile time.
3. Complexity and Undefined Boundaries
Certain complexities arise from algorithms that involve non-trivial iteration or strategy patterns that depend on runtime states or user-defined functors, making it difficult to define constexpr
behavior:
- Functors: If the user-provided callable is not
constexpr, it prevents the algorithm from beingconstexpr.
Technical Constraints
C++ has stringent rules about constexpr
functions:
- Must have a literal return type.
- Must not use variables of non-literal types.
- Must not perform operations not allowed in
constexprfunctions, such as dynamic memory allocation or virtual calls.
Which Algorithms Could Be constexpr
?
Despite these challenges, some standard algorithms have the potential to be constexpr
if certain conditions are met.
Potential constexpr
Candidates
For an algorithm to be a candidate for constexpr
:
- The input must be wholly
constexpr. - Must avoid operations with side effects.
- Must not depend on states or resources only available at runtime.
- Enhancing Iterator Compatibility: Introducing
constexprcompatible standard containers and iterators to ensure full compile-time traversability. - Augmenting Compiler Support: By enhancing compilers to better analyze and optimize
constexproperations across broader contexts.
Related reading
- Why C is not allowing non-member functions like C
- Why can't I remove a string from a stdset with stdremove_if?
- Why copy_n, fill_n and generate_n?
- Why do I have to always specify the range in STL''s algorithm functions explicitly, even if I want to work on the whole container?
- Why do we need to add a '0' null at the end of a character array in C?
- Why do we need virtual functions in C++?
- Why does boostequals require ranges to be copyable?
- Why does C++ code for testing the Collatz conjecture run faster than hand-written assembly?
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